WBJEE · Physics · Magnetic Properties of Matter
The intensity of magnetization of a bar magnet is \(5.0 \times 10^{4} \mathrm{Am}^{-1}\). The magnetic length and the area of cross-section of the magnet are \(12 \mathrm{cm}\) and \(1 \mathrm{cm}^{2}\) respectively. The magnitude of magnetic moment of this bar magnet is (in SI unit)
- A 0.6
- B 1.3
- C 1.24
- D 2.4
Answer & Solution
Correct Answer
(A) 0.6
Step-by-step Solution
Detailed explanation
We know that Intensity of magnetisation \(I=\frac{M}{V}\) [where \(M=\) magnetic moment, \(V=\) volume] So \(\begin{aligned} M=I V &=5.0 \times 10^{4} \times \frac{12}{100} \times \frac{1}{(100)^{2}} \\ &=60 \times 10^{4} \times 10^{-6}=0.6 \mathrm{Am}^{2} \end{aligned}\)
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