WBJEE · Physics · Dual Nature of Matter
Electric field component of an EM radiation varies with time as \(\mathrm{E}=\mathrm{a}\left(\cos \omega_{0} \mathrm{t}+\sin \omega \mathrm{t} \cos \omega_{0} \mathrm{t}\right)\), where ' \(\mathrm{a}\) ' is a constant and \(\omega=10^{15} \mathrm{sec}^{-1}, \omega_{0}=5 \times 10^{15} \mathrm{sec}^{-1}\). This radiation falls on a metal whose stopping potential is \(-2 \mathrm{ev}\). Then which of the following statement \((\mathrm{s})\) is/are true \(?\left(\mathrm{~h}=6.62 \times 10^{-34} \mathrm{~J}-\mathrm{S}\right)\)
- A For light of frequency \(\omega\), photoelectric effect is not possible
- B Stopping potential vs. frequency graph will be a straight line
- C The work function of the metal is \(-2 \mathrm{ev}\)
- D The maximum kinetic energy of the photo electrons is \(1.95 \mathrm{ev}\).
Answer & Solution
Correct Answer
(B) Stopping potential vs. frequency graph will be a straight line
Step-by-step Solution
Detailed explanation
Stopping potential \(=-2 \mathrm{~V} \Rightarrow \mathrm{KE}_{\max }=2 \mathrm{ev}\) (Option D incorrect) \(\mathrm{E}=\mathrm{a}\left(\cos \omega_{0} \mathrm{t}+\sin \omega \mathrm{t} \cos \omega_{0} \mathrm{t}\right)\)…
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