WBJEE · Chemistry · Coordination Compounds
Amongst \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}, \quad\left[\mathrm{Ni}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}_{2} ]\right.\), \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right.]\) and \(\left[\mathrm{Ni}\left(\mathrm{CN}_{4}\right)\right]^{2-}\) the paramagnetic species are
- A \(\left[\mathrm{NiCl}_{4}\right]^{2-},\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \cdot\left[\mathrm{Ni}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\)
- B \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right],\left[\mathrm{Ni}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}_{2}\right],\left[\mathrm{NiCl}_{4}\right]^{2-}\)
- C \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-} \cdot\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+},\left[\mathrm{NiCl}_{4}\right]^{2-}\)
- D \(\left[\mathrm{Nl}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}_{2}\right\}\left[\mathrm{Ni}(\mathrm{CO})_{4}\right\}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{NiCl}_{4}\right]^{2-},\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \cdot\left[\mathrm{Ni}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\)
Step-by-step Solution
Detailed explanation
Species having unpaired electrons are paramagnetic \[ \mathrm{Ni}^{2+}=[\mathrm{Ar}] 3 \mathrm{d}^{8} \] (i) In \([\left.\mathrm{NiCl}_{4}\right]^{2-}\) and \([\left.\operatorname{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) ligands \(\mathrm{Cl}^{-}\) and…
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