WBJEE · Chemistry · d and f Block Elements
\(4 f^2\) electronic configuration is found in
- A \(\mathrm{Pr}\)
- B \(\mathrm{Pr}^{3+}\)
- C \(\mathrm{Nd}^{3+}\)
- D \(\mathrm{Pm}^{3+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Pr}^{3+}\)
Step-by-step Solution
Detailed explanation
Hint : \(\operatorname{Pr}(59)=[X e] 4 f^3 6 s^2\) \(\therefore \mathrm{Pr}^{+3}=[\mathrm{Xe}] 4 \mathrm{f}^2\)
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