WBJEE · Physics · Waves and Sound
A uniform string of length \(L\) and mass \(M\) is fixed at both ends while it is subject to a
tension \(T\). It can vibrate at frequencies \((v)\) given by the formula (where \(n=1,2,3, \ldots)\)
- A \(v=\frac{n}{2} \sqrt{\frac{T}{M L}}\)
- B \(v=\frac{n}{2 L} \sqrt{\frac{T}{M}}\)
- C \(v=\frac{1}{2 n} \sqrt{\frac{T}{M L}}\)
- D \(v=\frac{n}{2} \sqrt{\frac{T L}{M}}\)
Answer & Solution
Correct Answer
(A) \(v=\frac{n}{2} \sqrt{\frac{T}{M L}}\)
Step-by-step Solution
Detailed explanation
The formula of frequency of 3 vibrations produced in tensed wire is \[ v=\frac{n}{2} \sqrt{\frac{T}{m}} \] \(m=\) Mass per unit length of the wire \(=\frac{M}{L}\) \(M=\) Mass of wire \(L=\) Length of wire \(n=\) Number of loops produced in wire…
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