WBJEE · Physics · Mathematics in Physics
The vectors are given by \(\dot{\mathbf{A}}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) and \(\mathbf{B}=3 \hat{\mathbf{i}}+6 \hat{\mathbf{j}}+2 \mathbf{k}\). Another vector \(\mathbf{C}\) has the same magnitude as \(\mathbf{B}\) but has the same direction as A. Then which of the following vectors represents C?
- A \(\frac{7}{3}(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+2 \hat{\mathrm{k}})\)
- B \(\frac{3}{7}(i-2 \hat{j}+2 \hat{k})\)
- C \(\frac{7}{9}(i-2 \hat{j}+2 \hat{k})\)
- D \(\frac{9}{7}(\vec{i}+2 \hat{j}+2 \hat{k})\)
Answer & Solution
Correct Answer
(A) \(\frac{7}{3}(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+2 \hat{\mathrm{k}})\)
Step-by-step Solution
Detailed explanation
(a) Given, \(A=i+2 j+2 \hat{k}\) and \(B=3 \hat{i}+6 j+2 \hat{k}\) So, \(\quad C=\frac{\hat{i}+2 \hat{j}+2 \hat{k}}{\sqrt{1+4+4}} \times \sqrt{3^{2}+6^{2}+2^{2}}\) \(=\frac{\hat{i}+2 \hat{j}+2 \hat{k}}{3} \times \sqrt{49}=\frac{7}{3}(\hat{i}+2 \hat{j}+2 \hat{\mathbf{k}})\)
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