WBJEE · Physics · Current Electricity
A circuit consists of three batteries of emf \(E_{1}=1 \mathrm{V}, E_{2}=2 \mathrm{V}\) and \(E_{3}=3 \mathrm{V}\) and internal resistances \(1 \Omega, 2 \Omega\) and \(1 \Omega\) respectively which are connected in parallel as shown in the figure. The potential difference between points \(P\) and \(Q\) is 
- A \(1.0 \mathrm{V}\)
- B \(2.0 \mathrm{V}\)
- C \(2.2 \mathrm{V}\)
- D \(3.0 \mathrm{V}\)
Answer & Solution
Correct Answer
(B) \(2.0 \mathrm{V}\)
Step-by-step Solution
Detailed explanation
\(1 \Omega .2 \Omega\) and \(1 \Omega\) are in parallel So, the required internal resistance…
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