WBJEE · Physics · Semiconductors

In the circuit shown, the value of \(\beta\) of the transistor is 48 . If the base current supplied is \(200 \mu \mathrm{A}\), what is the voltage at the terminal \(\mathrm{Y}\)?
- A \(0.2 \mathrm{~V}\)
- B \(0.5 \mathrm{~V}\)
- C \(4 \mathrm{~V}\)
- D \(4.8 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(0.2 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Hint: \(\beta=48\) \(l_{B}=200 \mu \mathrm{A}\) \(I_{C}=\beta I_{B}=48 \times 200 \times 10^{-6}\) \(V_{\mathrm{CC}}=I_{C} R_{C}+V_{C E} \therefore V_{C E}=5-\left(96 \times 10^{-4}\right) \times 500=5-4.8=0.2\) volt
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