WBJEE · Maths · Indefinite Integration
If \(\int e^{\sin x} \cdot\left[\frac{x \cos ^{3} x-\sin x}{\cos ^{2} x}\right] d x=e^{\sin x} f(x)+c\)
where c is constant of integration, then \(f(x)\) is
equal to
- A \(\sec x-x\)
- B \(x-\sec x\)
- C \(\tan x-x\)
- D \(x-\tan x\)
Answer & Solution
Correct Answer
(B) \(x-\sec x\)
Step-by-step Solution
Detailed explanation
We have. \(\int e^{\operatorname{cin} x}\left(\frac{x \cos ^{3} x-\sin x}{\cos ^{2} x}\right) d x=e^{\sin x} f(x)+c\) \(\int e^{\operatorname{sin} x}(x \cos x-\sec x \tan x) d x=e^{\sin x} f(x)+c\) \(\int e^{\operatorname{sin} x}(x \cos x-1+1-\sec x \tan x) d x\)…
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