WBJEE · Physics · Magnetic Properties of Matter
At two different places, the angles of dip are respectively \(30^{\circ}\) and \(45^{\circ} .\) At these two places the ratio of horizontal component of earth's magnetic field is
- A \(\sqrt{3}: \sqrt{2}\)
- B \(1: \sqrt{2}\)
- C 1: 2
- D \(1: \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{3}: \sqrt{2}\)
Step-by-step Solution
Detailed explanation
The horizontal component of earth's magnetic field is given by, \(H=R \cos \delta\) where, \(\delta\) is the angle of dip so \(H_{1}=R \cos 30^{\circ}\) and \(\mathrm{H}_{2}=\mathrm{Rcos} 45^{\circ}\)…
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