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WBJEE · Physics · Units and Dimensions

A spherical liquid drop is placed on a horizontal plane. A small disturbance causes the volume of the drop to oscillate. The time period of oscillation ( \(T\) ) of the liquid drop depends on radius \((n\) of the drop, density \((\rho)\) and surface tension (5) of the liquid. Which among the following will be a possible expression for \(T\) (where, \(k\) is a dimensionless constant)?

  1. A \(k \sqrt{\frac{\rho r}{S}}\)
  2. B \(k \sqrt{\frac{\rho^{2} r}{S}}\)
  3. C \(k \sqrt{\frac{\rho r^{3}}{S}}\)
  4. D \(k \sqrt{\frac{\rho r^{3}}{s^{2}}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(k \sqrt{\frac{\rho r^{3}}{S}}\)

Step-by-step Solution

Detailed explanation

According to the question. time period. \(T \alpha r^{a} p^{b} s^{c}\) \(r=k r^{a} p^{b} s^{c}\) Thus, putting dimension, we get Equating the dimensions of both sides, we get \([T]=[\mathrm{L}]^{a}\left[\mathrm{ML}^{-3}]^ \mathrm{b}\left[\mathrm{MT}^{-2} ]^c\right.\right.\)…