WBJEE · Maths · Heights and Distances
A balloon starting from rest is ascending from ground with uniform acceleration of \(4 \mathrm{ft} / \mathrm{sec}^2\). At the end of \(5 \mathrm{sec}\), a stone is dropped from it. If \(\mathrm{T}\) be the time to reach the stone to the ground and \(\mathrm{H}\) be the height of the balloon when the stone reaches the ground, then
- A \(\mathrm{T}=6 \mathrm{sec}\)
- B \(\mathrm{H}=112.5 \mathrm{ft}\)
- C \(T=5 / 2 \mathrm{sec}\)
- D \(225 \mathrm{ft}\)
Answer & Solution
Correct Answer
(C) \(T=5 / 2 \mathrm{sec}\)
Step-by-step Solution
Detailed explanation
Hint : Let after \(5 \mathrm{sec}\) ballon is at \(B\) Given: \(a=4 \mathrm{ft} / \sec ^2 u(\) Initial velocity \()=0\) \(\mathrm{t}=5 \mathrm{sec}\) Distance covered by ballon in \(5 \mathrm{sec}\);…
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