WBJEE · Chemistry · Ionic Equilibrium
The \(\mathrm{pH}\) of an aqueous solution of \(\mathrm{CH}_3 \mathrm{COONa}\) of concentrated \(\mathrm{C}(\mathrm{M})\) is given by
- A \(7-\frac{1}{2} \mathrm{pK}_{\mathrm{a}}-\frac{1}{2} \log \mathrm{C}\)
- B \(\frac{1}{2} \mathrm{pK}_{\mathrm{w}}+\frac{1}{2} \mathrm{pK}_{\mathrm{b}}+\frac{1}{2} \log \mathrm{C}\)
- C \(\frac{1}{2} \mathrm{pK}_{\mathrm{w}}-\frac{1}{2} \mathrm{pK}_{\mathrm{b}}-\frac{1}{2} \log \mathrm{C}\)
- D \(\frac{1}{2} \mathrm{pK}_{\mathrm{w}}+\frac{1}{2} \mathrm{pK}_{\mathrm{a}}+\frac{1}{2} \log \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2} \mathrm{pK}_{\mathrm{w}}+\frac{1}{2} \mathrm{pK}_{\mathrm{a}}+\frac{1}{2} \log \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Hints : In case of Hydrolysis of salt of weak acid and strong base, the \(\mathrm{pH}\) is given by \(\frac{1}{2} \mathrm{pK}_{\mathrm{w}}+\frac{1}{2} \mathrm{pK}_{\mathrm{a}}+\frac{1}{2} \log \mathrm{c}\)
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