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WBJEE · Physics · Magnetic Effects of Current

A proton of mass \(m\) moving with a speed \(v\) ( \(< < \) c. velocity of light in vacuum) completes circular orbit in time \(T\) in a uniform Whetic ficld. If the speed of the proton is increased to \(\sqrt{2}\) v, what will be time needed to plete the circular orbit?

  1. A \(\sqrt{T}\)
  2. B \(T\)
  3. C \(\frac{T}{\sqrt{2}}\)
  4. D \(\frac{T}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(T\)

Step-by-step Solution

Detailed explanation

\(\because\) When a charged particle moves at a circular path in uniform magnetic field, it time period is independent from its speed. Time period of proton will not change with change in its speed.