WBJEE · Physics · Electrostatics
A charge of 0.8 coulomb is divided into two charges \(Q_{1}\) and \(Q_{2}\). These are kept at a separation of \(30 \mathrm{cm}\). The force on \(Q_{1}\) is maximum when
- A \(Q_{1}=Q_{2}=0.4 \mathrm{C}\)
- B \(Q_{1}=0.8 \mathrm{C}, Q_{2}\) negligible
- C \(Q_{1}\) negligible, \(Q_{2}=0.8 \mathrm{C}\)
- D \(Q_{1}=0.2 \mathrm{C}, Q_{2}=0.6 \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(Q_{1}=Q_{2}=0.4 \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\[ \frac{Q_{1}}{30 c m} \stackrel{Q_{2}}{6} \] Checking the given options one by one (i) \(Q_{1}=Q_{2}=0 \cdot 4 \mathrm{C}\) The force on \(Q_{1}\) due to \(Q_{2}\)…
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