WBJEE · Physics · Oscillations
A particle vibrating simple harmonically hat an acceleration of \(16 \mathrm{cms}^{-2}\) when it is at distance of \(4 \mathrm{cm}\) from the mean position, lt time period is
- A \(1 \mathrm{s}\)
- B \(2.572 \mathrm{s}\)
- C \(3.142 \mathrm{s}\)
- D \(6.028 \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(3.142 \mathrm{s}\)
Step-by-step Solution
Detailed explanation
In SHM, the acceleration of vibrating particle is proportional to displacement \[ \begin{aligned} |\mathbf{a}| &=\omega^{2} x \\ \text { Here } a=16 \mathrm{cm} / \mathrm{s}^{2} \\ &=16 \times 10^{-2} \mathrm{m} / \mathrm{s}^{2} \end{aligned} \] Displacement,…
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