WBJEE · Physics · Dual Nature of Matter
If the kinetic energies of an electron, an alpha particle and a proton having same de-Broglie wavelength are \(\varepsilon_1, \varepsilon_2\) and \(\varepsilon_3\) respectively, then
- A \(\varepsilon_1>\varepsilon_3>\varepsilon_2\)
- B \(\varepsilon_1=\varepsilon_2=\varepsilon_2\)
- C \(\varepsilon_1 < \varepsilon_3 < \varepsilon_2\)
- D \(\varepsilon_1>\varepsilon_2>\varepsilon_3\)
Answer & Solution
Correct Answer
(A) \(\varepsilon_1>\varepsilon_3>\varepsilon_2\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mk}}}, \sqrt{\mathrm{mk}}=\mathrm{const}\) \(\mathrm{k} \propto \frac{1}{\mathrm{~m}}, \varepsilon_1>\varepsilon_3>\varepsilon_2\)
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