WBJEE · Physics · Work Power Energy
A body of density \(1.2 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\) is dropped from rest from a height \(1 \mathrm{~m}\) into a liquid of density \(2.4 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\). Neglecting all dissipative effects, the maximum depth to which the body sinks before returning to float on the surface is
- A \(0.1 \mathrm{~m}\)
- B \(1 \mathrm{~m}\)
- C \(0.01 \mathrm{~m}\)
- D \(2 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(1 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{d}=1.2 \times 10^{3}, \mathrm{~h}=1 \mathrm{~m}, \rho=2.4 \times 10^{3}\) By work Energy Theorem,…
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