WBJEE · Physics · Mathematics in Physics
A particle is moving uniformly in a circular path of radius \(r\). When it moves through an angular displacement \(\theta\), then the magnitude of the corresponding linear displacement will be
- A \(2 r \cos \left(\frac{\theta}{2}\right)\)
- B \(2 r \cot \left(\frac{\theta}{2}\right)\)
- C \(2 r \tan \left(\frac{\theta}{2}\right)\)
- D \(2 r \sin \left(\frac{\theta}{2}\right)\)
Answer & Solution
Correct Answer
(D) \(2 r \sin \left(\frac{\theta}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(\ln \Delta A O B \quad \sin \frac{\theta}{2}=\frac{A B}{A O}\) \(\Leftrightarrow A O=r)\)…
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