WBJEE · Chemistry · Redox Reactions
You are supplied with \(500 \mathrm{mL}\) each of \(2 \mathrm{N} \mathrm{HCl}\) and \(5 \mathrm{N} \mathrm{HCl}\). What is the maximum volume of 3M HCl that you can prepare using only these two solutions?
- A \(250 \mathrm{mL}\)
- B \(500 \mathrm{nL}\)
- C \(750 \mathrm{mL}\)
- D \(1000 \mathrm{mL}\)
Answer & Solution
Correct Answer
(C) \(750 \mathrm{mL}\)
Step-by-step Solution
Detailed explanation
As per given relation, \(\begin{array}{l} N_{1} V_{1}+N_{2} V_{2}=N\left(V_{1}+V_{2}\right) \\ N_{1}=2 N_{2}=5 \\ V_{1}=500 V_{2}=\operatorname{say}-x \end{array}\) Thus, \(2 \times 500+5 x=3(x+500)\) or \(2 x=500^{\circ}\) ie. \(x=250\) Hence, maximum volume of…
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