WBJEE · Chemistry · Solid State
An element crystallizes in a body centred cubic lattice. The edge length of the unit cell is \(200 \mathrm{pm}\) and the density of the element is \(5.0 \mathrm{~g} \mathrm{~cm}^{-3}\). Calculate the number of atoms in \(100 \mathrm{~g}\) of this element.
- A \(2.5 \times 10^{23}\)
- B \(2.5 \times 10^{24}\)
- C \(5.0 \times 10^{23}\)
- D \(5.0 \times 10^{24}\)
Answer & Solution
Correct Answer
(D) \(5.0 \times 10^{24}\)
Step-by-step Solution
Detailed explanation
\rho_{\text {unit cell }}(\mathrm{g} / \mathrm{cc})=\frac{\mathrm{Z} \times \mathrm{M} \cdot \mathrm{Mass}(\mathrm{g} / \mathrm{mol})}{\mathrm{N}_{\mathrm{A}}\left(\mathrm{mol}^{-1}\right) \times(\mathrm{a} \mathrm{pm})^{3} \times 10^{-30}} \quad \mathrm{Z}_{\text {B.c.c }}=2 or…
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