WBJEE · Physics · Magnetic Effects of Current
An electron in a circular orbit of radius \(0.05 \mathrm{nm}\) performs \(10^{16}\) revolutions per second. The maghetic moment due to this rotation of electron is (in \(\mathrm{Am}^{2}\) )
- A \(2.16 \times 10^{-23}\)
- B \(3.21 \times 10^{-22}\)
- C \(3.21 \times 10^{-24}\)
- D \(1.26 \times 10^{-23}\)
Answer & Solution
Correct Answer
(D) \(1.26 \times 10^{-23}\)
Step-by-step Solution
Detailed explanation
Given, \(r=0.05 \mathrm{nm}=0.05 \times 10^{-9} \mathrm{m}\) \[ \begin{array}{l} \qquad\left(\because 1 \mathrm{nm}=10^{-9} \mathrm{m}\right) \\ n=10^{16} \text { revolutions } \\ e=1.6 \times 10^{-19} \mathrm{C} \end{array} \] We know that The magnetic moment \(M=A L\)…
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