WBJEE · Maths · Circle
A variable circle passes through the fixed point \(A(p, q)\) and touches \(X\) -axis. The locus of the other end of the diameter through \(A\) is
- A \((x-p)^{2}=4 q y\)
- B \((x-q)^{2}=4 p y\)
- C \((y-p)^{2}=4 q x\)
- D \((y-q)^{2}=4 p x\)
Answer & Solution
Correct Answer
(A) \((x-p)^{2}=4 q y\)
Step-by-step Solution
Detailed explanation
In a circle, \(A B\) is a diameter where the coordinate of \(A\) is \((p, q)\) and let the coordinate of \(B\left(x_{1}, y_{1}\right)\) Equation of circle in diameter form is \[ (x-p)\left(x-x_{1}\right)+(y-q)\left(y-y_{1}\right)=0 \]…
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