WBJEE · Maths · Sequences and Series
The three sides of a right angled triangle are in GP (geometric progression). If the two acute angles be \(\alpha\) and \(\beta\), then tan \(\alpha\) and tan \(\beta\) are
- A \(\frac{\sqrt{5}+1}{2}\) and \(\frac{\sqrt{5}-1}{2}\)
- B \(\sqrt{\frac{\sqrt{5}+1}{2}}\) and \(\sqrt{\frac{\sqrt{5}-1}{2}}\)
- C \(\sqrt{5}\) and \(\frac{1}{\sqrt{5}}\)
- D \(\frac{\sqrt{5}}{2}\) and \(\frac{2}{\sqrt{5}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{\sqrt{5}+1}{2}}\) and \(\sqrt{\frac{\sqrt{5}-1}{2}}\)
Step-by-step Solution
Detailed explanation
Let \(\Delta A B C\) be a right angled triangle at \(B\). Let \(\angle A\) and \(\angle C\) be \(\alpha\) and \(\beta\) Since, sides are in GP so sides are \(a,\) ar, ar \(^{2}\)…
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