WBJEE · Physics · Mechanical Properties of Fluids
A cylinder of height his filled with wator and is kept on a block of height \(h / 2\) The level of water in the cylinder is kept constant. Four holes numbered 1,2,3 and 4 are at the side of the cylinder and at heights \(0, h / 4, h / 2\) and \(3 h / 4,\) respectively. When all four holes are openned together, the hole from which water will reach farthest distance on the plane \(P Q\) is the hole number.
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
Height of the cylinder from the level \(P O\) is \(H=h+\frac{h}{2}=\frac{3 h}{2}\) To cover maximum distance along the plane \(P Q\), height of the hole is \(=\frac{3 h}{2} \times \frac{1}{2}=\frac{3 h}{4}\) This height corresponds to hole (2).
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