WBJEE · Physics · Atomic Physics
The ionization energy of hydrogen is \(13.6 \mathrm{eV}\). The energy of the photon released when an electron jumps from the first excited state \((n=2)\) to the ground state of a hydrogen atom is
- A \(3.4 \mathrm{eV}\)
- B \(4.53 \mathrm{eV}\)
- C \(10.2 \mathrm{eV}\)
- D \(13.6 \mathrm{eV}\)
Answer & Solution
Correct Answer
(C) \(10.2 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
Energy required to removed electron in th \((n=2)\) stage The energy of the photon…
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