WBJEE · Physics · Ray Optics
The convex lens \(\left(L_1\right.\) and \(\left.L_2\right)\) of equal focal length \(f\) are placed at a distance \(\frac{f}{2}\) apart. An object is placed at a distance \(4 f\) in the left of \(L_1\) as shown in figure. The final image is at
- A \(\frac{5 \mathrm{f}}{11}\) right of \(\mathrm{L}_2\)
- B \(\frac{5 f}{11}\) left of \(L_2\)
- C \(5 f\) right of \(\mathrm{L}_2\)
- D 5 left of \(L_2\)
Answer & Solution
Correct Answer
(A) \(\frac{5 \mathrm{f}}{11}\) right of \(\mathrm{L}_2\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ & \frac{1}{v}-\frac{1}{-4 f}=\frac{1}{f} \Rightarrow \frac{1}{v}=\frac{1}{f}-\frac{1}{4 f} \Rightarrow \frac{1}{v}=\frac{4-1}{4 f} \Rightarrow v=\frac{4 f}{3} \\ & u_2=\frac{4 f}{3}-\frac{f}{2}=\frac{8 f-3 f}{6}…
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