WBJEE · Maths · Area Under Curves
The area bounded by the curves \(x=4-y^2\) and the \(Y\)-axis is
- A 16 sq. unit
- B \(\frac{32}{3}\) sq. unit
- C \(\frac{16}{3}\) sq. unit
- D 32 sq. unit
Answer & Solution
Correct Answer
(B) \(\frac{32}{3}\) sq. unit
Step-by-step Solution
Detailed explanation
Hint: \(x=4-y^2 \Rightarrow y^2=-x+4\) \(x=0 \Rightarrow y^2=4 \Rightarrow y= \pm 2\) Area bounded by the curve \(x=4-y^2\) and \(y\)-axis is, \(=2 \int_0^2 x d y=2 \int_0^2\left(4-y^2\right) d y=2\left[4 y-\frac{y^3}{3}\right]_0^2=2\left(8-\frac{8}{3}\right)=\frac{32}{3}\) sq.…
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