WBJEE · Physics · Dual Nature of Matter
The de-Broglie wavelength of an electron is the same as that of a \(50 \mathrm{keV}\) X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is (the energy equivalent of electron mass is \(0.5 \mathrm{MeV}\) )
- A 01:50
- B 01:20
- C 20: 1
- D 50: 1
Answer & Solution
Correct Answer
(C) 20: 1
Step-by-step Solution
Detailed explanation
de-Broglie wavelength \(\lambda=\frac{h}{\sqrt{2 m K}}\) The kinetic energy of the electron \[ K_{\text {electron }}=\frac{1}{2 m} \cdot \frac{h^{2}}{\lambda^{2}} \] Where \(h=\) Planck constant \(\lambda=\) wavelength The photon energy…
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