WBJEE · Maths · Pair of Lines
Without changing the direction of the axes, the origin is transferred to the point (2,3) . Then the equation \(x^{2}+y^{2}-4 x-6 y+9=0\) changes to
- A \(x^{2}+y^{2}+4=0\)
- B \(x^{2}+y^{2}=4\)
- C \(x^{2}+y^{2}-8 x-12 y+48=0\)
- D \(x^{2}+y^{2}=9\)
Answer & Solution
Correct Answer
(B) \(x^{2}+y^{2}=4\)
Step-by-step Solution
Detailed explanation
Put \(x=x^{\prime}+2\) and \(\quad y=y^{\prime}+3\) \(\therefore \quad x^{2}+y^{2}-4 x-6 y+9=0\)…
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