WBJEE · Maths · Basic of Mathematics
The value of \(\left(\frac{1}{\log _3 12}+\frac{1}{\log _4 12}\right)\) is
- A 0
- B \(\frac{1}{2}\)
- C 1
- D 2
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
Hints : \(\log _{12} 3+\log _{12} 4=\log _{12} 12=1\)
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