WBJEE · Physics · Waves and Sound
The fundamental frequency of a closed pipe is equal to the frequency of the second harmonic of an open pipe. The ratio of their lengths is
- A \(1: 2\)
- B \(1: 4\)
- C \(1: 8\)
- D \(1: 16\)
Answer & Solution
Correct Answer
(B) \(1: 4\)
Step-by-step Solution
Detailed explanation
Let the length of closed pipe is \(L_{1}\) and that of pipe is \(L_{2}\). Fundamental frequency of closed pipe, \(v_{1}=\frac{v}{4 L_{1}}\) and frequency of second harmonic of open pipe. \[ v_{2}=2 \times \frac{v}{2 L_{2}} \] Given, \[ v_{1}=v_{2} \] \(i, \theta\)…
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