WBJEE · Maths · Trigonometric Ratios & Identities
The value of \(\frac{\sin 55^0-\cos 55^{\circ}}{\sin 10^0}\) is
- A \(\frac{1}{\sqrt{2}}\)
- B 2
- C 1
- D \(\sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
Hints: \(\frac{\sin 55-\sin 35}{\sin 10}=\frac{2 \cos 45 \cdot \sin 10}{\sin 10}=\sqrt{2}\)
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