WBJEE · Maths · Limits
The value of \(\operatorname{Lt}_{x \rightarrow 0} \frac{\sin ^2 x+\cos x-1}{x^2}\) is
- A 1
- B \(\frac{1}{2}\)
- C \(-\frac{1}{2}\)
- D 0
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Hints: \(\operatorname{Lim}_{x \rightarrow 0} \frac{\sin ^2 x+\cos x-1}{x^2}=\operatorname{Lim}_{x \rightarrow 0} \frac{\cos x-\cos ^2 x}{x^2}=\operatorname{Lim}_{x \rightarrow 0}\left(\frac{1-\cos x}{x^2}\right) \cos x\)…
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