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WBJEE · Maths · Differentiation

If \(f(x)=x^{n}, n\) being a non-negative integer, then the values of \(n\) for which
\(f^{\prime}(\alpha+\beta)=f^{\prime}(\alpha)+f^{\prime}(\beta)\) for all \(\alpha, \beta>0\) is

  1. A 1
  2. B 2
  3. C 0
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(C) 0

Step-by-step Solution

Detailed explanation

We have, \(\begin{aligned} f(x) &=x^{n} \\ f^{\prime}(x) &=n x^{n-1} \end{aligned}\) Now, \(f^{\prime}(\alpha+\beta)=f^{\prime}(\alpha)+f^{\prime}(\beta)\) \(\Rightarrow \quad n(\alpha+\beta)^{n-1}=n \alpha^{n-1}+n \beta^{n-1}\) \(\Rightarrow(a+\beta)^{n-1}=a^{n-1}+\beta^{n-1}\)…