WBJEE · Maths · Parabola
The focus of the conic \(x^{2}-6 x+4 y+1=0\) is
- A (2,3)
- B (3,2)
- C (3,1)
- D (1,4)
Answer & Solution
Correct Answer
(C) (3,1)
Step-by-step Solution
Detailed explanation
We have, \[ x^{2}-6 x+4 y+1=0 \] \(\Rightarrow \quad(x-3)^{2}-9+4 y+1=0\) \(\Rightarrow \quad(x-3)^{2}+4 y-8=0\) \(\Rightarrow \quad(x-3)^{2}=-4(y-2)\) It represents parabola whose vertex is (3,2) \(\therefore\) Focus \(=(3,-1+2)=(3,1)\)
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