WBJEE · Chemistry · Practical Chemistry
To a solution of a colourless efflorescent sodium salt, when dilute acid is added, a colourless gas is evolved along with formation of a white precipitate. Acidified dichromate solution turns green when the colourless gas is passed through it. The sodium salt is
- A \(\mathrm{Na}_{2} \mathrm{SO}_{3}\)
- B \(\mathrm{Na}_{2} \mathrm{~S}\)
- C \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\)
- D \(\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\)
Step-by-step Solution
Detailed explanation
Hint: \(\underset{\text { (colouriess, efflorescent) }}{\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}(\mathrm{~s})}+2 \mathrm{H}^{+}(\mathrm{dil} .) \rightarrow \mathrm{S}(\mathrm{s})+2 \mathrm{Na}^{+}(\mathrm{aq})+\mathrm{SO}_{2} \uparrow+\mathrm{H}_{2} \mathrm{O}(\ell)\)…
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