WBJEE · Maths · Application of Derivatives
Time period \(T\) of a simple pendulum of length \(l\) is given by \(T=2 \pi \sqrt{\frac{l}{g}}\). If the length is increased by \(2 \%\), then an approximate change in the time period is
- A \(2 \%\)
- B \(1 \%\)
- C \(\frac{1}{2} \%\)
- D None of these
Answer & Solution
Correct Answer
(B) \(1 \%\)
Step-by-step Solution
Detailed explanation
Given, \(T=2 \pi \sqrt{\frac{1}{g}}\) On differentiating w.r.t. \(l,\) we get…
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