WBJEE · Maths · Differential Equations
The integrating factor of the differential equation \(x \log x \frac{d y}{d x}+y=2 \log x\) is given by
- A \(\mathrm{e}^{\mathrm{x}}\)
- B \(\log x\)
- C \(\log (\log \mathrm{x})\)
- D \(x\)
Answer & Solution
Correct Answer
(B) \(\log x\)
Step-by-step Solution
Detailed explanation
Hints : \(\frac{d y}{d x}+\frac{1}{x \log x} \cdot y=\frac{2}{x}\) \[ \begin{aligned} & \text { If }=e^{\int \frac{1}{x \log x} d x}=e^{\int \frac{1 / x}{\log x} d x} \\ & =e^{\log (\log x)}=\log x \end{aligned} \]
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