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WBJEE · Maths · Three Dimensional Geometry

Angle between two diagonals of a cube will be

  1. A \(\cos ^{-1}\left(\frac{1}{3}\right)\)
  2. B \(\sin ^{-1}\left(\frac{1}{3}\right)\)
  3. C \(\frac{\pi}{2}-\cos ^{-1}\left(\frac{1}{3}\right)\)
  4. D \(\frac{\pi}{2}-\sin ^{-1}\left(\frac{1}{3}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\cos ^{-1}\left(\frac{1}{3}\right)\)

Step-by-step Solution

Detailed explanation

d.c. of diagonal \(\mathrm{OC}: \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\) or, \(-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}\) d.c. of diagonal AD : \(-\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\) or,…