WBJEE · Maths · Area Under Curves
The area bounded by \(y^2=4 x\) and \(x^2=4 y\) is
- A \(\frac{20}{3}\) sq. unit
- B \(\frac{16}{3}\) sq. unit
- C \(\frac{14}{3}\) sq. unit
- D \(\frac{10}{3}\) sq. unit
Answer & Solution
Correct Answer
(B) \(\frac{16}{3}\) sq. unit
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Hints: } A=\int_0^4\left(\sqrt{4 \mathrm{x}}-\frac{\mathrm{x}^2}{4}\right) \mathrm{dx} \\ & \left.=2 \cdot \frac{2}{3}\left(\mathrm{x}^{3 / 2}\right)_0^4-\frac{1}{4.3}\right)\left(\mathrm{x}^3\right)_0^4 \\ & =\frac{4}{3}\left[4^{3 /…
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