WBJEE · Chemistry · Classification of Elements and Periodicity in Properties
\(5.75 \mathrm{mg}\) of sodium vapour is converted to sodium ion. If the ionisation energy of sodium is \(490 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and atomic weight is 23 units, the amount of energy needed for this conversion will be
- A \(1.96 \mathrm{~kJ}\)
- B \(1960 \mathrm{~kJ}\)
- C \(122.5 \mathrm{~kJ}\)
- D \(0.1225 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(D) \(0.1225 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Na}(\mathrm{g}) \longrightarrow \mathrm{Na}^{+}(\mathrm{g})+\mathrm{e}^{-}\) \(1 \mathrm{~mol} \mathrm{Na}(\mathrm{g})\) requires \(490 \mathrm{~kJ} /\) mol for ionization. \(\therefore \quad \frac{5.75 \times 10^{-3}}{23}\) mol \(\quad\) requires…
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