WBJEE · Maths · Circle
A point \(P\) lies on the circle \(x^{2}+y^{2}=169\). If \(Q=(5,12)\) and \(R=(-12,5),\) then the \(\angle Q P R\) is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \[ x^{2}+y^{2}=169 \] Its centre \(=(0,0)\) and radius \(=13\) Now, slope of \(O R=\frac{-5}{12}=m_{1}\left(\because\right.\) slope \(\left.=\frac{y_{2}-y}{x_{2}-x}\right)\) and slope of \(O Q=\frac{12}{5}=m_{2}\)…
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