WBJEE · Maths · Circle
The common chord of the circles \(x^{2}+y^{2}-4 x-4 y=0 \quad\) and \(\quad 2 x^{2}+2 y^{2}=32\) subtends at the origin an angle equal to
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Given, equation of circles are \(x^{2}+y^{2}-4 x-4 y=0\) and \(2 x^{2}+2 y^{2}=32\) or \(x^{2}+y^{2}-4 x-4 y=0\) and \(x^{2}+y^{2}=16\) \(\therefore\) Equation of common chord is \(\left(x^{2}+y^{2}-4 x-4 y\right)-\left(x^{2}+y^{2}-16\right)=0\)…
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