WBJEE · Maths · Complex Number
The general value of the real angle \(\theta\), which satisfies the equation. \((\cos \theta+i \sin \theta)(\cos 2 \theta+i \sin 2 \theta) \ldots(\cos n \theta+t \sin n \theta)=1\) is given by, (assuming \(k\) is an integer)
- A \(\frac{2 k \pi}{n+2}\)
- B \(\frac{4 k \pi}{n(n+1)}\)
- C \(\frac{4 x \pi}{n+1}\)
- D \(\frac{6 k \pi}{n(n+1)}\)
Answer & Solution
Correct Answer
(B) \(\frac{4 k \pi}{n(n+1)}\)
Step-by-step Solution
Detailed explanation
We have, \((\cos\theta+i\sin\theta)(cos2\theta+isin2\theta)...(cosn\theta+isinn\theta) = 1\) \(\Rightarrow e^{i\theta}.e^{i(2\theta)}.e^{i(3\theta)}. ...e^{i(n\theta)} = 1\) \(\Rightarrow e^{i\theta(1+2+3+...+n}=1\) \(\Rightarrow e^{\frac{in(n+1)\theta}{2}}=1\)…
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