WBJEE · Maths · Binomial Theorem
\[
\text { If }(2 \leq r \leq n), \text { then }{ }^{n} C_{r}+2 \cdot{ }^{n} C_{r+1}+{ }^{n} C_{r+2} \text { is }
\]
equal to
- A \(2 \cdot{ }^{n} C_{r+7}\)
- B \("^{-1} C_{r+1}\)
- C \({ }^{n+2} C_{r+2}\)
- D \(^{n+1} C_{r}\)
Answer & Solution
Correct Answer
(C) \({ }^{n+2} C_{r+2}\)
Step-by-step Solution
Detailed explanation
\({ }^{n} C_{r}+2 \cdot{ }^{n} C_{r+1}+{ }^{n} C_{r+2}\) \(={ }^{n} C_{r}+{ }^{n} C_{r+1}+{ }^{n} C_{r+1}+{ }^{n} C_{r+2}\) \(={ }^{n+1} C_{r+1}+{ }^{n+1} C_{r+2}\) \(\quad\left(\because{ }^{n} C_{r}+{ }^{n} C_{r+1}={ }^{n+1} C_{r+1}\right)\) \(={ }^{n+2} C_{r+2}\)
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