WBJEE · Maths · Parabola
The axis of the parabola \(x^{2}+2 x y+y^{2}-5 x+5 y-5=0\) is
- A \(x+y=0\)
- B \(x+y-1=0\)
- C \(x-y+1=0\)
- D \(x-y=\frac{1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(A) \(x+y=0\)
Step-by-step Solution
Detailed explanation
Given, equation \(x^{2}+2 x y+y^{2}-5 x+5 y-5=0\) \(\Rightarrow(x+y)^{2}=5 x-5 y+5\) \(\Rightarrow(x+y)^{2}=5(x-y+1)\) \(\therefore\) Axis of the parabola is \(x+y=0\)
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