WBJEE · Maths · Functions
\(\mathrm{A}=\{1,2,3,4\}, \mathrm{B}=\{1,2,3,4,5,6\}\) are two sets, and function \(\mathrm{f}: \mathrm{A} \rightarrow \mathrm{B}\) is defined by \(\mathrm{f}(\mathrm{x})=\mathrm{x}+2 \forall \mathrm{x} \in \mathrm{A}\), then the function \(\mathrm{f}\) is
- A bijective
- B onto
- C one-one
- D many-one
Answer & Solution
Correct Answer
(C) one-one
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{f}(\mathrm{x})=\mathrm{f}(\mathrm{y}) \Rightarrow \mathrm{x}+2=\mathrm{y}+2 \Rightarrow \mathrm{x}=\mathrm{y} \quad \therefore\) one-one
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