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WBJEE · Maths · Complex Number

If \(\left|Z_1\right|=\left|Z_2\right|=\left|Z_3\right|=1\) and \(Z_1+Z_2+Z_3=0\), then the area of the triangle whose vertices are \(Z_1, Z_2, Z_3\) is

  1. A \(\frac{3 \sqrt{3}}{4}\)
  2. B \(\frac{\sqrt{3}}{4}\)
  3. C \(1\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{3 \sqrt{3}}{4}\)

Step-by-step Solution

Detailed explanation

Given: - \(\left|Z_1\right|=\left|Z_2\right|=\left|Z_3\right|=1\) - \(Z_1+Z_2+Z_3=0\) Concept: If three complex numbers lie on the unit circle and their sum is zero, they form an equilateral triangle on the Argand plane. For equilateral triangle with side \(a=1\), the area is:…