WBJEE · Maths · Three Dimensional Geometry
The equation of the plane through the intersection of the planes \(x+y+z=1\) and \(2 x+3 y-z+4\) and parallel to the \(x\)-axis is
- A \(y+3 z+6=0\)
- B \(y+3 z-6=0\)
- C \(y-3 z+6=0\)
- D \(y-3 z-6=0\)
Answer & Solution
Correct Answer
(C) \(y-3 z+6=0\)
Step-by-step Solution
Detailed explanation
\(\quad(2 x+3 y-z+4)+\lambda(x + y+z-1)=0\) \(\overrightarrow{\mathrm{n}}=(2+\lambda) \hat{\mathrm{i}}+(3+\lambda) \hat{\mathrm{j}}+(-1+\lambda) \hat{\mathrm{k}}\) \(\overrightarrow{\mathrm{n}} \cdot \overrightarrow{\mathrm{i}}=0 \Rightarrow \lambda=-2\)…
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